Two electrical voltages have a total of 126 volts. If one voltage is 32 more than the other, find the voltages.
Started off with x =126V
Y = 32v
now stuck
Sum and difference:
(sum+difference)/2 = larger number
(sum-difference)/2 = smaller number
If x is the smaller voltage, then x+32 is the larger one.
x + x+32 = 126
Now find x, and you have the smaller voltage.
To find the voltages, let's set up a system of equations based on the given information:
Let's assume that one of the voltages is x and the other voltage is y. We know that the two voltages add up to 126 volts:
x + y = 126
We also know that one voltage is 32 volts more than the other:
x = y + 32
Since we have two equations, we can solve them simultaneously to find the values of x and y.
Let's start by solving the second equation for x:
x = y + 32
Next, substitute this expression for x into the first equation:
(y + 32) + y = 126
Now simplify the equation:
2y + 32 = 126
Subtract 32 from both sides:
2y = 94
Divide both sides by 2:
y = 47
Now, substitute the value of y back into the expression for x:
x = y + 32
x = 47 + 32
x = 79
So the two voltages are 79 volts and 47 volts.