The probability that their baby will be a carrier of the gene for PKU is (A) _3/4_. The probability that their baby will be affected by PKU is (B) ____. If both genotypes were Pp, the probability that their baby would be affected by PKU would be (C) _1/4______.

Question

The probability that their baby will be a carrier of the gene for PKU is (A) _3/4_. The probability that their baby will be affected by PKU is (B) ____. If both genotypes were Pp, the probability that their baby would be affected by PKU would be (C) _1/4______.

need help on the second answer thought it was 1/2 but it was wrong

Answer 1

Is the PKU gene represented by P or p? If the latter, C is correct for the last statement.

Cannot respond to first two questions, because parental genotypes are not given.

Answer 2

To determine the probability that their baby will be affected by PKU (phenylketonuria), we need to understand the inheritance pattern of the gene for PKU.

PKU is an autosomal recessive disorder, which means that it requires two copies of the abnormal gene to be present for the individual to be affected. Individuals who carry only one copy of the abnormal gene are called carriers, but they do not show symptoms of the disorder.

Let's denote the normal gene as "P" and the abnormal gene as "p." Since both parents are carriers and have the genotype Pp, the possible combinations of genes their baby can inherit are as follows:

1. P from the mother and P from the father (PP): This combination does not result in PKU.
2. P from the mother and p from the father (Pp): This combination also does not result in PKU but makes the baby a carrier.
3. p from the mother and P from the father (pP): This combination does not result in PKU but makes the baby a carrier.
4. p from the mother and p from the father (pp): This combination results in the baby being affected by PKU.

Based on these possible combinations, the probability that their baby will be affected by PKU is 1/4 or 25%. Therefore, the correct answer for (B) is 1/4, not 1/2.

It is important to note that this calculation assumes that both parents are carriers and that the probability of them passing on the abnormal gene is equal for each possible combination. These probabilities are based on genetic principles and Punnett squares, which is a visual tool to understand the inheritance of traits.

The probability that their baby will be a carrier of the gene for PKU is (A) ___3/4_______. The probability that their baby will be affected by PKU is (B) __________. If both genotypes were Pp, the probability that their baby would be affected by PKU would be (C) ___1/4______.

Is the PKU gene represented by P or p? If the latter, C is correct for the last statement.

To determine the probability that their baby will be affected by PKU (phenylketonuria), we need to understand the inheritance pattern of the gene for PKU.

The probability that their baby will be a carrier of the gene for PKU is (A) _3/4_. The probability that their baby will be affected by PKU is (B) ____. If both genotypes were Pp, the probability that their baby would be affected by PKU would be (C) _1/4______.