posted by Lya on .
A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.2 s later. If the speed of sound is 340 m/s, how high is the cliff?
vo= 0; s=340 m/s; t= 3.2s
t1+t2= 3.2 s
I used Eq: h= vo*t^1+1/2at^2
t^2= 340/4.9= 69.38 s
t^1= -66.18 s
Sorry, I don't know if I am doing this right.I still can't figure out how to get h=?
t=3.2s (this time includes both the time taken for the rock to fall and the time taken by sound to travel to the listener from the ocean)
change in time=t-d/s
work this out and solve for d, which is the height of the cliff