Write the following in a+bi form
(-5-i)/(3-3i)
-5/3 and 1/3i
(-5/2i)/(-1/5i)
23 and 0i
(-2i)^3
-2 and 0
Im having trouble with these probems and here is my answers. PLEASE HELP
(-5 - i)/(3 - 3i)
= (-5 - i)/(3 - 3i) * (3+3i)/(3+3i)
= (-15-15i -3i -3i^2)/(9 - 9i^2)
= (-15 - 18i + 3)/(9 + 9)
= (-12 - 18i)/18
= -2/3 - i
(-5/2)i / ((-1/5)i )
= (-5/2) / (-1/5)
= (-2/5)(-5/1)
= 2
(-2i)^3
= -8i^3
now i^3 = (i^2)(i) = -i
so -8i^3
= -8(-i) = 8i
I do not understand your answers.
Why do you have "and" between the numbers ?