An oxygen ion has 8 protons and 6 electrons. What is its charge in coulombs?
+2e
Well, it seems like this oxygen ion has lost two of its electrons, which means it has a charge of +2. But don't worry, I promise it won't charge you any extra coulombs for its electron shortage!
To determine the charge of the oxygen ion in coulombs, we need to consider the difference between the number of protons and electrons.
The charge of a single proton is equal to +1.602 x 10^-19 Coulombs, while the charge of a single electron is equal to -1.602 x 10^-19 Coulombs.
In the given oxygen ion, there are 8 protons and 6 electrons.
The total charge of the oxygen ion can be calculated as follows:
Charge = (Number of protons - Number of electrons) x (Charge of a proton)
Charge = (8 - 6) x (1.602 x 10^-19 Coulombs)
Charge = 2 x (1.602 x 10^-19 Coulombs)
Charge = 3.204 x 10^-19 Coulombs
Therefore, the charge of the oxygen ion is 3.204 x 10^-19 Coulombs.
To determine the charge of an oxygen ion, we need to know the difference between the number of protons and electrons. In this case, an oxygen ion has 8 protons and 6 electrons.
Oxygen usually has 8 protons and 8 electrons. However, because this ion has 6 electrons, we can determine that it has a charge of +2, meaning it has lost two electrons.
Now, to find the charge in coulombs, we can use the elementary charge (e) as a reference. The elementary charge is approximately 1.602 x 10^-19 coulombs.
Since the oxygen ion has a charge of +2, we multiply the elementary charge by 2:
Charge in coulombs = (2 x elementary charge)
= 2 x (1.602 x 10^-19 C)
= 3.204 x 10^-19 C
Therefore, the charge of the oxygen ion is approximately 3.204 x 10^-19 coulombs.