I seriously need help.
1) What is the pOH of a strong acid with a pH of 2?
2)What is the molarity of a strong acid equal to?
1) pH + pOH = pKw = 14.
You know pH and pKw, solve for pOH. Not that hard if you can subtract.
2) I don't know where you're headed but
M = mols/L or
M strong acid is M of H^+ or
pH = -log M.
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Of course, I'm here to help! Let's break down your questions one by one.
1) To find the pOH of a strong acid with a pH of 2, you need to understand the relationship between pH and pOH. The pH and pOH scale are opposite logarithmic scales that measure the concentration of hydrogen ions (H+) and hydroxide ions (OH-) in a solution.
The formula to find pOH is as follows:
pOH = 14 - pH
Since you mentioned that the pH of the strong acid is 2, you can substitute that value into the formula:
pOH = 14 - 2
pOH = 12
Therefore, the pOH of the strong acid with a pH of 2 is 12.
2) The molarity of a strong acid refers to the concentration of acid in a solution and is usually expressed as moles of acid per liter of solution (mol/L or M).
For example, if you have a solution with 1 mole of a strong acid dissolved in 1 liter of water, the molarity would be 1 M (1 mol/L).
It is important to note that the molarity of a strong acid is always equal to the number of moles of acid divided by the volume of the solution in liters.
To determine the molarity of a strong acid, you would need to know the number of moles of acid and the volume of the solution in liters. Once you have this information, you can use the formula:
Molarity (M) = moles of acid / volume of solution (in liters)
For example, if you have 0.5 moles of a strong acid dissolved in 0.25 liters of water, the molarity would be:
Molarity = 0.5 mol / 0.25 L
Molarity = 2 M
Therefore, the molarity of the strong acid in this example would be 2 M.
I hope this helps! If you have any further questions, feel free to ask.