I'm confused with this one, here's what i got
45.0 v/ 40.0Ω = 1.125 A
is the answer b?
A 10.0 Ω resistor is in parallel with a 30.0 Ω resistor and supplied by a 45.0 V battery. What is the total current drawn from the battery?
0.003 A
1.10 A
6.00 A
338 A
NO!!!
10 in PARALLEL with 30
1/R = 1/R1 + 1/R2
or
R = R1 R2 /(R1+R2)
R = 10*30 / (40)
= 7.5
45/7.5 = 6 Amps
okay, thx, i take online school and it's much harder for me
To find the total current drawn from the battery, we need to use Ohm's Law and the concept of parallel resistors.
First, let's calculate the individual currents for each resistor using Ohm's Law:
For the 10.0 Ω resistor:
Current (I1) = Voltage (V) / Resistance (R) = 45.0 V / 10.0 Ω = 4.50 A
For the 30.0 Ω resistor:
Current (I2) = Voltage (V) / Resistance (R) = 45.0 V / 30.0 Ω = 1.50 A
Now, for resistors in parallel, the total current (Itotal) is the sum of the individual currents:
Itotal = I1 + I2 = 4.50 A + 1.50 A = 6.00 A
Therefore, the correct answer is:
6.00 A
So, the answer is not b.