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March 5, 2015

March 5, 2015

Posted by **Scott** on Thursday, May 22, 2014 at 12:48pm.

- Data Management -
**MathMate**, Thursday, May 22, 2014 at 9:59pmProbability of getting the right answer for 1 question = 1 choice out of 5, or p=1/5.

Assuming independence among the 10 questions, probability of getting all 10 right = p^{10}

Probability of passing (getting 6 or more right out of 10) using binomial probabilities

=10C6*p^6q^4 + 10C7*p^7q^3 + 10C8*p^8q^2 + 10C9*p^9q + 10C10p^10

=(10752+1536+144+8+1)/9765625

= 12441/9765625

= 0.00127 approx.

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