What is the probability that a number picked from the set {–4, –3, –2, –1, 0, 1, 2, 3, 4, 5} will be a solution of 2x + 5 > 1?
• 20%
• 30%
• 70%
• 80%
It's 70% for anyone else looking
2x+5 > 1
x > -2
So, of the 10 numbers, how many are greater than -2?
To find the probability that a number picked from the given set will be a solution of the equation 2x + 5 > 1, we need to determine how many numbers in the set satisfy the given inequality.
Let's solve the inequality first:
2x + 5 > 1
Subtracting 5 from both sides, we get:
2x > 1 - 5
2x > -4
Dividing both sides by 2, we get:
x > -2
Now, we can check which numbers in the set satisfy this inequality and count them:
In the given set, {–4, –3, –2, –1, 0, 1, 2, 3, 4, 5}, the numbers greater than -2 are: {0, 1, 2, 3, 4, 5}.
Thus, 6 numbers satisfy the inequality out of the total 10 numbers in the set.
The probability of picking a number satisfying the inequality is given by: (Number of favorable outcomes) / (Total number of outcomes)
So, the probability is given by: 6 / 10 = 0.6 = 60%
Therefore, the correct answer is not provided in the options given.