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January 29, 2015

January 29, 2015

Posted by **godofwar** on Wednesday, May 21, 2014 at 10:41am.

- physics -
**MathMate**, Wednesday, May 21, 2014 at 12:40pmGiven 4 resistances, and we need to sort out which one is which.

Assume that the resistances are non-zero.

We know that two resistances in parallel is always smaller than any of the two.

Similarly, two resistances in series is always greater than any of the two.

So the two single resistances are the middle values, namely 4Ω and 12Ω.

Let's check:

In series, total = 4+12=16Ω ok

In parallel, R=1/(1/4+1/12)=1/(4/12)=3Ω

does not equal the smallest of 2Ω.

Could you check if there is a typo in the question?

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