A new cruise ship line has just launched 3 new ships: the Pacific, the Caribbean, and the Mediterranean. The Caribbean has 32 more rooms then the Pacific.

The Mediterranean has 38 fewer rooms than FOUR times the number of rooms on the Pacific. Find the number of rooms for each of the ships if the total number of rooms for the 3 ships is 828.

Pacific = x

Caribbean = x+32
Medi = 4x - 38

x+x+32+4x-38 = 828

you solve it, it is easy

i came here bc i needed the help not someone to tell me it is easy.

Let's start by assigning variables to represent the number of rooms on each ship. Let P, C, and M represent the number of rooms on the Pacific, the Caribbean, and the Mediterranean, respectively.

According to the given information, the Caribbean has 32 more rooms than the Pacific, so we can write the equation:

C = P + 32

The Mediterranean has 38 fewer rooms than four times the number of rooms on the Pacific. Mathematically, this can be expressed as:

M = 4P - 38

The total number of rooms for the three ships is 828, so we can sum up the number of rooms:

P + C + M = 828

Now let's substitute the expressions for C and M into the total equation to get an equation in terms of P only:

P + (P + 32) + (4P - 38) = 828

Simplify the equation:

6P - 6 = 828

Add 6 to both sides:

6P = 834

Divide both sides by 6:

P = 139

Now that we know the number of rooms on the Pacific (P = 139), we can substitute it back into the equations for C and M to find their values:

C = P + 32 = 139 + 32 = 171

M = 4P - 38 = 4(139) - 38 = 556 - 38 = 518

Therefore, the Pacific has 139 rooms, the Caribbean has 171 rooms, and the Mediterranean has 518 rooms.