A basketball has a radius of 11,5 cm. how many times would this basketball roll if it was pushed from one end of the court to the other end of the court 28 m away? Give your answer correct to the nearest whole number.
since the circumference of the ball is 2pi*11.5 = 72.26 cm, divide that into 2800cm to see how many times it rolls.
38.75
To find the number of times the basketball would roll from one end of the court to the other, we need to calculate the circumference of the basketball's path and divide it by the circumference of the basketball.
The circumference of a circle can be calculated using the formula: C = 2πr, where C is the circumference and r is the radius.
Given that the radius of the basketball is 11.5 cm, we can calculate its circumference as follows:
C = 2πr
C = 2 * 3.14 * 11.5 cm
C ≈ 72.28 cm
Now, we can find the number of times the basketball would roll by dividing the distance between the two ends of the court (28 m) by the circumference of the basketball (72.28 cm):
Distance = 28 m
Since the units don't match, we need to convert meters to centimeters.
1 meter = 100 centimeters
So, the distance in centimeters = 100 cm/m * 28 m ≈ 2800 cm
Number of rolls = Distance / Circumference
Number of rolls = 2800 cm / 72.28 cm
Number of rolls ≈ 38.69
Rounding it to the nearest whole number, the basketball would roll approximately 39 times.