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Calculus

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How do you find the derivative of y=sinxtan^3(x)?

  • Calculus -

    use the product rule

    y = sinx tan^3(x)
    y' = cosx tan^3(x) + sinx (tan^3(x))'
    for tan^3(x), use the chain rule and you get

    y' = cosx tan^3(x) + sinx(3tan^2(x) sec^2(x))

    Now we can massage things a bit:

    sin^3/cos^2 + 3sin^3/cos^4
    sin^3*cos/cos^3 + 3sin^3/cos^4
    tan^3(cos + 3sec)

    lots of ways

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