Monday

December 22, 2014

December 22, 2014

Posted by **Anonymous** on Wednesday, May 14, 2014 at 10:48pm.

- Calculus -
**Steve**, Thursday, May 15, 2014 at 12:34amuse the product rule

y = sinx tan^3(x)

y' = cosx tan^3(x) + sinx (tan^3(x))'

for tan^3(x), use the chain rule and you get

y' = cosx tan^3(x) + sinx(3tan^2(x) sec^2(x))

Now we can massage things a bit:

sin^3/cos^2 + 3sin^3/cos^4

sin^3*cos/cos^3 + 3sin^3/cos^4

tan^3(cos + 3sec)

lots of ways

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