algebra
posted by Mary Ann on .
If $32,500 is invested at 69% for 3 years find the future value if the interest is compounded the following ways.
annually, semiannually, quarterly, monthly, daily, every minute (N525,600)
continuously, simple (not compounded.
Thank you for your time.

Po = $32,500 @ 69%? for 3 years.
P1 = Po(1+r)^n. Compounded annually.
P1 = 32,500(1+0.69)^3 = $156,871.29
P2 = 32,500(1+0.69/2)^6 = 192,405.32
P3 = 32,500(1+0.69/4)^12 = 219,400.48
P4 = 32,500(1+0.69/12)^36 = 243,207.46
P5 = 32,500(1+0.69/365)^1095=257,053.95
P6 = 32,500(1+0.69/525,600)^1,576,800 =
257,556.40
P7 = Po*e^(r*t) = 32,500*e^(0.69*3) =
257,556.75
P8 = Po + Po*r*t=32000 + 32,500*0.69*3 = 98,240. Simple Int.