Posted by Mary Ann on Wednesday, May 14, 2014 at 8:55pm.
If $32,500 is invested at 69% for 3 years find the future value if the interest is compounded the following ways.
annually, semiannually, quarterly, monthly, daily, every minute (N525,600)
continuously, simple (not compounded.
Thank you for your time.

algebra  Henry, Friday, May 16, 2014 at 9:01pm
Po = $32,500 @ 69%? for 3 years.
P1 = Po(1+r)^n. Compounded annually.
P1 = 32,500(1+0.69)^3 = $156,871.29
P2 = 32,500(1+0.69/2)^6 = 192,405.32
P3 = 32,500(1+0.69/4)^12 = 219,400.48
P4 = 32,500(1+0.69/12)^36 = 243,207.46
P5 = 32,500(1+0.69/365)^1095=257,053.95
P6 = 32,500(1+0.69/525,600)^1,576,800 =
257,556.40
P7 = Po*e^(r*t) = 32,500*e^(0.69*3) =
257,556.75
P8 = Po + Po*r*t=32000 + 32,500*0.69*3 = 98,240. Simple Int.
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