B=allele for black color
b=allele for the recessive color
When you perform a cross between the two guinea pigs, there is a 75% chance that EACH offspring will express black as the phenotype, and there is 25% chance that EACH guinea pig will express the recessive phenotype. Out of four offspring, you would expect one of the offspring to display the recessive phenotype, but the chances that all of the offspring from the cross between the guniea pigs will display black as the phenotype are higher compared to at least one of the offspring displaying the recessive phenotype.
The results of a cross are the following:
1 BB : 2 Bb : 1bb
3 Black : 1 Recessive
You can look at the results of a cross in two ways: One, the chances of ONE offspring expressing the black phenotype is 3/4 or 75%, or two, you can say that the out of four children, three should express the black phenotype, and one should express the recessive phenotype. However, the results are indicative of the chances that ONE offspring will inherit a specific combination of alleles, or express a specific phenotype.
The chances that all four will express the dominant phenotype is the following:
(3/4)^4=81/256 or 32%
The chances that three will express the dominant phenotype and one will will express the recessive phenotype is the following:
(3/4)^3*(1/4)=27/256 or 11%
So, is it basically just that the guinea pig offspring will have a higher chance of being black than it would for 3 offspring being black and the other one being the recessive color?