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January 21, 2017
Posted by **Jasmine** on Wednesday, May 14, 2014 at 7:41pm.

3x^2+4y^2=12

- Trig -
**Reiny**, Wednesday, May 14, 2014 at 8:00pm3x^2 + 4y^2 = 12

divide by 12

x^2/4 + y^2/3 = 1

we know sin^2 t + cos^2 t = 1

so sin^2 t = x^2/4 = (x/2)^2

---> sin t x/s ----> x = 2sin t

and

cos^2 t = y^2/3 = (y/√3)^2

cos t = y/√3

----> y = √3cos t

x = 2sint

y = √4cost

confirmation:

http://www.wolframalpha.com/input/?i=x+%3D+2sint+%2C+y+%3D+√3cost