Posted by **Anonymous** on Wednesday, May 14, 2014 at 1:20am.

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 25m/s. The ball's height h (in meters) after t seconds is given by the following.

Find all values of t for which the ball's height is 12 meters.

Round your answer(s) to the nearest hundredth.

- Algebra -
**Steve**, Wednesday, May 14, 2014 at 5:44am
h(t) = 2+25t-4.9t^2

h=12 when

2+25t-4.9t^2 = 12

t= 0.44 and 4.66 seconds

- Algebra -
**Jenny**, Sunday, January 22, 2017 at 7:06pm
To find when the ball's height is

7

meters, we substitute

7

for

h

and solve for

t

.

=7+2−25t5t2

In order to solve for

t

, we first rewrite the equation in the form

=+at2+btc0

.

=+−5t225t50

Next, we use the quadratic formula to solve for

t

.

=t−b±−b24ac2a

Our equation has

=a5

,

=b−25

, and

=c5

.

Another way

We use these values in the formula.

t

=−−25±−−252·4·55·25

=25±52510

We get that

t

can be either of two values to solve the equation.

=t=−25525100.2087…

or

=t=+25525104.7912…

Rounding these values to the nearest hundredth, we get

=t0.21

or

=t4.79

.

So, the ball's height is

7

meters at approximately

0.21

seconds (on its way up) or

4.79

seconds (on its way down).

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