Posted by Maura on Tuesday, May 13, 2014 at 12:29pm.
(a)
(f(3+.03)-f(3))/.03 = (3.1209-3)/.03 = 4.03
(b)
f'(x) = 2x-2
f'(3) = 4
(c)
f(3) = 3
So, now you have a point and a slope. The line is easy to express.
(d)
Now just plug 2.98 into that line.
(e)
where is f'(x) = 0?
Thanks!