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November 29, 2014

November 29, 2014

Posted by **Maura** on Tuesday, May 13, 2014 at 12:29pm.

a) Estimate f'(3) using h = 0.03

b) Find the exact value for f'(3)

c) Give the equation of the tangent line to f(x) at x=3

d) Use the tangent line to estimate f(2.98)

e) Critical points

- Calc -
**Steve**, Tuesday, May 13, 2014 at 12:37pm(a)

(f(3+.03)-f(3))/.03 = (3.1209-3)/.03 = 4.03

(b)

f'(x) = 2x-2

f'(3) = 4

(c)

f(3) = 3

So, now you have a point and a slope. The line is easy to express.

(d)

Now just plug 2.98 into that line.

(e)

where is f'(x) = 0?

- Calc -
**Maura**, Tuesday, May 13, 2014 at 12:50pmThanks!

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