If it helps the answer according to this ACT compass sample test questions print out is 6.93.
How to solve it is the question ...
C is a 90 degree angle.
AB is 8 and the hypotenuse.
AC is the base .... we don't know it's length.
It's on page 14 if you google this -
2014 ACT In the right triangle shown below, the length of AB is 8 units
recall your basic trig definitions, and draw a diagram. You will see that
BC/8 = sin 60°
BC/8 = 0.866
BC = 6.93
If this gave you difficulties, you have some serious reviewing ahead.
Dude,
throw me a bone ....? I'm try'n to learn.
I see that A sin 60 degrees is equal to BC/8 (8 = the hypotenuse).
C is a right angle.
BC is the height.
Wait. I think I see it now....?
Because Sin equals BC(opposite)/H(8)and we know that the result of this equals .866, we can multiply .866 x 8 which will give us 6.928?
Dude,
throw me a bone ....? I'm try'n to learn.
I see that A sin 60 degrees is equal to BC/8 (8 = the hypotenuse).
C is a right angle.
BC is the height.
Wait. I think I see it now....?
Because Sin equals BC(opposite)/H(8)and we know that the result of this equals .866, we can multiply .866 x 8 which will give us 6.928?
To solve the problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b).
In this case, we are given that AB is the hypotenuse and has a length of 8 units, and the angle C is 90 degrees. We want to find the length of AC.
Let's use the Pythagorean theorem to solve for AC:
c^2 = a^2 + b^2
In this triangle, AC is the base, so it is side a, and AB is the hypotenuse, so it is side c. We'll call the length of AC "x".
Therefore, we have:
8^2 = x^2 + b^2
64 = x^2 + b^2
Since we don't know the length of b, we can't solve for x directly. However, we do know that angle C is a right angle (90 degrees), so we can use the fact that the cosine of angle C is equal to the adjacent side (AC) divided by the hypotenuse (AB).
cos(C) = AC / AB
cos(90) = x / 8
0 = x / 8
x = 0
Therefore, the length of AC is 0 units.
Since we're given that AB = 8 and AC = 0, we have a right triangle with one side having a length of 8 and the other side having a length of 0, which doesn't follow the properties of a right triangle. It seems there may be an error in the problem or the given values.