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January 29, 2015

January 29, 2015

Posted by **Joe** on Tuesday, May 13, 2014 at 9:31am.

How to solve it is the question ...

C is a 90 degree angle.

AB is 8 and the hypotenuse.

AC is the base .... we don't know it's length.

It's on page 14 if you google this -

2014 ACT In the right triangle shown below, the length of AB is 8 units

- Trig -
**Steve**, Tuesday, May 13, 2014 at 12:57pmrecall your basic trig definitions, and draw a diagram. You will see that

BC/8 = sin 60°

BC/8 = 0.866

BC = 6.93

If this gave you difficulties, you have some serious reviewing ahead.

- Trig -
**Joe**, Tuesday, May 13, 2014 at 3:19pmDude,

throw me a bone ....? I'm try'n to learn.

I see that A sin 60 degrees is equal to BC/8 (8 = the hypotenuse).

C is a right angle.

BC is the height.

Wait. I think I see it now....?

Because Sin equals BC(opposite)/H(8)and we know that the result of this equals .866, we can multiply .866 x 8 which will give us 6.928?

- Trig -
**Joe**, Wednesday, May 14, 2014 at 8:11amDude,

throw me a bone ....? I'm try'n to learn.

I see that A sin 60 degrees is equal to BC/8 (8 = the hypotenuse).

C is a right angle.

BC is the height.

Wait. I think I see it now....?

Because Sin equals BC(opposite)/H(8)and we know that the result of this equals .866, we can multiply .866 x 8 which will give us 6.928?

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