If a rectangle has a perimeter of 70 meters and a length of 17 meters, what is its width?

P=2l+2w
Whats the next step?

next step: plug in what you know

70 = 2(17) + 2w

Now just solve for w.

P=2l+2w

70 = 2(17) + 2w
70 = 34 +2w
70-34 = 34-34 +2w
36 = 2w
w = 18

The next step is to substitute the values into the formula and solve for the width (w).

Given:
Perimeter (P) = 70 meters
Length (l) = 17 meters

Substituting these values into the perimeter formula: P = 2l + 2w.

70 = 2(17) + 2w

Now, simplify the equation by performing the multiplication:
70 = 34 + 2w

Next, subtract 34 from both sides of the equation:
70 - 34 = 34 - 34 + 2w
36 = 2w

Finally, solve for the width (w) by dividing both sides of the equation by 2:
36/2 = 2w/2
18 = w

Therefore, the width of the rectangle is 18 meters.