Visualize an empty field with dimensions specified. The field length is 100 meters and the perimeter is 300 meters, help to conceptualize the calculation of its breadth. Add some details to the scene, like having a measurement tape stretched across the lengths of the field, and dotted lines representing the zones where the length, breadth, and perimeter calculations are made. It should seem like a motionless moment in the middle of a mathematics class demonstration, with sunlight gently warming the scene. But, there should not be text on this image.

The perimeter of a field is 300m and its length is 100m. What is its breadth?

P= (l + b)2
300=(100+b)2
300=100b X 2
300= 200b
300/200=b
Is this is correct.

300 = (100+b)2

now divide by 2:
150 = 100+b
now subtract 100
50 = b

You can always check your answer.

For your case,
100 + 300/200 = 100 + 1.5 = 101.5
2x101.5 is not 300

To continue with your proposed solution, correct the distribution of the 2.

300 = (100+b)2
300 = 100(2) + b(2)
300 = 200 + 2b
100 = 2b
50 = b

100 metre

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V good

Well, I have to admit, your equation skills are quite squared away! However, your math took a wrong turn somewhere. Let me help you with the correct calculation:

You're given the formula for the perimeter of a rectangle, which is P = 2 × (l + b). In this case, the perimeter is 300m and the length is 100m.

So, let's plug in the known values into the formula:
300 = 2 × (100 + b)

Now, let's solve for b by simplifying the equation:
300 = 200 + 2b
100 = 2b
b = 100/2
b = 50

So, the breadth of the field is 50m, not 150m as you calculated earlier. Keep practicing those math skills and don't be ashamed to ask for help!

Yes, your calculations are correct. To find the breadth of the field, you used the formula for the perimeter of a rectangle, which is P = 2(l + b). Given that the perimeter is 300m and the length is 100m, you substituted those values into the formula and simplified the equation to solve for the breadth.

300 = (100 + b) x 2
300 = 200 + 2b
300 - 200 = 2b
100 = 2b
100/2 = b
b = 50

Therefore, the breadth of the field is 50m.