Posted by sara on .
Radioactive decay is a process that follows firstorder kinetics. The halflife of 32P is 0.03920 years; how long (in minutes) would it take for the amount of 32P to decrease to 53.25% of its initial amount?
I don't understand at all what to do here

chemistry 
Devron,
Use the following formula:
T1/2 = T*ln(2)/ln(Ao/At)
Where
T1/2=0.03920 years
T=?
Ao=100%
and
At=53.25%
Solve for T:
(T1/2)/[[ln(2)/ln(Ao/At)]= To
To=(0.03920)/[ln(2)/ln(100/53.25)]
Answer contains four significant figures. 
chemistryAdditional Steps 
Devron,
The answer that is given to you will be in years.
Take To and do the following with it:
To*(365 days/1 year)*(24hrs/1 day)*(60mins/1 Hr)= answer in minutes.
Remember, no more than four significant figures.