Posted by sara on Sunday, May 11, 2014 at 9:29pm.
Radioactive decay is a process that follows first-order kinetics. The half-life of 32P is 0.03920 years; how long (in minutes) would it take for the amount of 32P to decrease to 53.25% of its initial amount?
I don't understand at all what to do here
- chemistry - Devron, Sunday, May 11, 2014 at 9:45pm
Use the following formula:
T1/2 = T*ln(2)/ln(Ao/At)
Solve for T:
Answer contains four significant figures.
- chemistry-Additional Steps - Devron, Sunday, May 11, 2014 at 9:59pm
The answer that is given to you will be in years.
Take To and do the following with it:
To*(365 days/1 year)*(24hrs/1 day)*(60mins/1 Hr)= answer in minutes.
Remember, no more than four significant figures.
Answer This Question
More Related Questions
- Chemistry - 32P is a radioactive isotope with a half-life of 14.3 days. If you ...
- chem - Radioactive substances decay by first-order kinetics. How many years ...
- Chemistry - Gallium65, a radioactive isotope of gallium, decays by first order-...
- chemistry - If there are 80 milligrams of a radioactive element decays to 10 ...
- Chemistry - The radioactive nuclide 18F decays by first order kinetics with a ...
- Math - D.E.Q. - The half-life of a radioactive isotope is the amount of time it ...
- Chemistry - I've figured out most of it. I'm not sure how to find the percentage...
- chemistry - The isotype caesium -137, which has a half life of 30 years, is a ...
- Science- Radioactive Dating - Which of the following statements about ...
- chemistry - How long will it take for 25% of the C-14 atoms in a sample of C-14 ...