Posted by sara on Sunday, May 11, 2014 at 9:29pm.
Radioactive decay is a process that follows firstorder kinetics. The halflife of 32P is 0.03920 years; how long (in minutes) would it take for the amount of 32P to decrease to 53.25% of its initial amount?
I don't understand at all what to do here

chemistry  Devron, Sunday, May 11, 2014 at 9:45pm
Use the following formula:
T1/2 = T*ln(2)/ln(Ao/At)
Where
T1/2=0.03920 years
T=?
Ao=100%
and
At=53.25%
Solve for T:
(T1/2)/[[ln(2)/ln(Ao/At)]= To
To=(0.03920)/[ln(2)/ln(100/53.25)]
Answer contains four significant figures.

chemistryAdditional Steps  Devron, Sunday, May 11, 2014 at 9:59pm
The answer that is given to you will be in years.
Take To and do the following with it:
To*(365 days/1 year)*(24hrs/1 day)*(60mins/1 Hr)= answer in minutes.
Remember, no more than four significant figures.
Answer This Question
Related Questions
 Chemistry  32P is a radioactive isotope with a halflife of 14.3 days. If you ...
 chem  Radioactive substances decay by firstorder kinetics. How many years ...
 Math  D.E.Q.  The halflife of a radioactive isotope is the amount of time it ...
 chemistry  If there are 80 milligrams of a radioactive element decays to 10 ...
 Chemistry  Gallium65, a radioactive isotope of gallium, decays by first order...
 calculus  Carbon14 is a radioactive substance produced in the Earth's ...
 chemistry  The isotype caesium 137, which has a half life of 30 years, is a ...
 college  a certain radioactive isotope has a half life or 850 years.how many ...
 Chemistry  The radioactive nuclide 18F decays by first order kinetics with a ...
 Calc  A sample of a radioactive substance decayed to 93.5% of its original ...
More Related Questions