A spinner numbered 1-10 is spun. what is the probability of spinning a multiple of 3 and a multiple of 2?

From 1 to 10, isn't 6 the only number divisible by both 3 and 2 ?

so prob = 1/10

A multiple of 3

To find the probability of spinning a number that is both a multiple of 3 and a multiple of 2 on a spinner numbered 1-10, we need to determine how many numbers satisfy this condition and divide it by the total number of possible outcomes.

Multiples of 3: 3, 6, 9.
Multiples of 2: 2, 4, 6, 8, 10.

The common numbers that are multiples of both 3 and 2 are only one: 6.

Total possible outcomes: 10 (since there are 10 numbers on the spinner).

Therefore, the probability of spinning a number that is both a multiple of 3 and a multiple of 2 is 1 out of 10, which can be written as 1/10 or 0.1.

To find the probability of spinning a multiple of 3 and a multiple of 2, we first need to determine how many numbers on the spinner satisfy both conditions.

Multiples of 3: 3, 6, 9
Multiples of 2: 2, 4, 6, 8, 10

To find the numbers that are multiples of both 3 and 2, we need to take the intersection of these two sets. In this case, the only number that appears in both sets is 6.

So, there is only 1 number on the spinner that is both a multiple of 3 and a multiple of 2, which is 6.

Next, we need to determine the total number of possible outcomes. Since there are 10 numbers on the spinner (from 1 to 10), there are 10 possible outcomes.

Finally, we can calculate the probability. Probability is the ratio of the favorable outcomes to the total outcomes. In this case, there is 1 favorable outcome (spinning a 6) and 10 total outcomes.

Therefore, the probability of spinning a multiple of 3 and a multiple of 2 is 1/10, or 0.1 (or 10%).