2nd posting - my mistake

When will the dependent variable in the equation y= sqrt [x+4-3] equal or exceed 4
• x ≥ –0.17
• x ≥ 45 ** is it this one?
• x ≥ 48
• x ≥ 53

why not just say "x+1" instead of "x+4-3"?

And if x>=45 works, why not x>=48? or x>=53?

I still suspect a typo.

I may not be writing it correctly but I did find out it was x =45.

Thanks for you help.

To determine when the dependent variable in the equation y = sqrt [x + 4 - 3] will equal or exceed 4, we can start by setting up the equation:

sqrt [x + 4 - 3] ≥ 4

Now, let's solve for x:

First, square both sides of the inequality to eliminate the square root:

[x + 4 - 3] ≥ 4^2

Simplifying further:

[x + 1] ≥ 16

To isolate x, subtract 1 from both sides:

[x] ≥ 16 - 1

[x] ≥ 15

Therefore, the correct answer would be:

x ≥ 15

Out of the given options:

- x ≥ –0.17
- x ≥ 45
- x ≥ 48
- x ≥ 53

The option that satisfies the inequality is x ≥ 15.