2nd posting - my mistake
When will the dependent variable in the equation y= sqrt [x+4-3] equal or exceed 4
• x ≥ –0.17
• x ≥ 45 ** is it this one?
• x ≥ 48
• x ≥ 53
why not just say "x+1" instead of "x+4-3"?
And if x>=45 works, why not x>=48? or x>=53?
I still suspect a typo.
I may not be writing it correctly but I did find out it was x =45.
Thanks for you help.
To determine when the dependent variable in the equation y = sqrt [x + 4 - 3] will equal or exceed 4, we can start by setting up the equation:
sqrt [x + 4 - 3] ≥ 4
Now, let's solve for x:
First, square both sides of the inequality to eliminate the square root:
[x + 4 - 3] ≥ 4^2
Simplifying further:
[x + 1] ≥ 16
To isolate x, subtract 1 from both sides:
[x] ≥ 16 - 1
[x] ≥ 15
Therefore, the correct answer would be:
x ≥ 15
Out of the given options:
- x ≥ –0.17
- x ≥ 45
- x ≥ 48
- x ≥ 53
The option that satisfies the inequality is x ≥ 15.