When will the dependent variable in the equation Y=[(sqrt)(x+4-3)] equal or exceed 4?

• x ≥ –0.17
• x ≥ 45
• x ≥ 48
• x ≥ 53

we want

√(x+4-3) >= 4
I suspect a typo due to the odd nature of the expression.

Yes, I am not sure how to write it out. Do you know where I can get the symbol for square root? I can't find it in the "Symbol" tools.

It wasn't the root symbol (which you can copy and paste fro my posting), but the "x+4-3" expression. Why not just say "x+1"? I suspect that is not what you had in mind. Was it √(x+4)-3 or something else?

To determine when the dependent variable in the equation Y = sqrt(x+4-3) will equal or exceed 4, we need to solve for x. Here's how you can do it:

1. Start with the equation Y = sqrt(x+4-3).

2. Square both sides of the equation to eliminate the square root. This gives us Y^2 = x+4-3.

3. Simplify the equation by combining like terms. We get Y^2 = x+1.

4. Now, we want to find the values of x that make Y^2 equal to or greater than 16 (since we want Y to be equal to or greater than 4). So, we have Y^2 ≥ 16.

5. Substitute x+1 for Y^2 in the inequality to get (x+1) ≥ 16.

6. Subtract 1 from both sides of the inequality to isolate x. This gives us x ≥ 15.

Therefore, the correct answer is x ≥ 15. None of the options provided match this answer, so none of them are correct.

To solve this problem, you need to find the values that make Y^2 equal to or greater than 16. The options provided don't provide the correct solution.