Post a New Question


posted by .

If 50 ft lbs of work is done on the same spring (in part a) in order to compress it, by how much is the spring shortened?

*Information on part (a) is 400 #/in is the k constant and 1.75" is the compression.

50 ft lbs = 600 in lbs

equation is: 1/2 * 600" lb * 1.75"^2 = 918.75 lbs???

I'm looking for the length in this question, how do I get that?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question