Posted by **Adam -Please check if I'm Correct** on Thursday, May 8, 2014 at 1:26pm.

If 50 ft lbs of work is done on the same spring (in part a) in order to compress it, by how much is the spring shortened?

*Information on part (a) is 400 #/in is the k constant and 1.75" is the compression.

50 ft lbs = 600 in lbs

equation is: 1/2 * 600" lb * 1.75"^2 = 918.75 lbs???

I'm looking for the length in this question, how do I get that?

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