posted by Adam -Please check if I'm Correct on .
If 50 ft lbs of work is done on the same spring (in part a) in order to compress it, by how much is the spring shortened?
*Information on part (a) is 400 #/in is the k constant and 1.75" is the compression.
50 ft lbs = 600 in lbs
equation is: 1/2 * 600" lb * 1.75"^2 = 918.75 lbs???
I'm looking for the length in this question, how do I get that?