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chemistry

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a 2.00 L ballon at 25 degrees celcius and 745mmHg floats on an altitude where the temperature is 10 degrees celcius and the air pressure is 700mmHg. what is the new volume othe balloon

  • chemistry -

    Use the combined gas law:

    P1V1/T1=P2V2/T2

    Where

    P1=745mmHg
    V1=2.00L
    T1=273K+25=298.15K
    P2=700mmHg
    V2=?
    T2=273.15+10=283.15K

    Solve for V2:

    V2=(P1/P2)*(T2/T1)*V1


    Answer should contain three significant figures.

  • chemistry -

    1.06L

  • chemistry -

    Convert pressures from mmHg to atm then use combined gas law to solve for the new volume. You get 2.06 Liters

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