Posted by **lola** on Thursday, May 8, 2014 at 3:53am.

a 2.00 L ballon at 25 degrees celcius and 745mmHg floats on an altitude where the temperature is 10 degrees celcius and the air pressure is 700mmHg. what is the new volume othe balloon

- chemistry -
**Devron**, Thursday, May 8, 2014 at 6:25am
Use the combined gas law:

P1V1/T1=P2V2/T2

Where

P1=745mmHg

V1=2.00L

T1=273K+25=298.15K

P2=700mmHg

V2=?

T2=273.15+10=283.15K

Solve for V2:

V2=(P1/P2)*(T2/T1)*V1

Answer should contain three significant figures.

- chemistry -
**Bob**, Sunday, December 6, 2015 at 12:43pm
1.06L

- chemistry -
**Sal**, Sunday, March 13, 2016 at 3:50pm
Convert pressures from mmHg to atm then use combined gas law to solve for the new volume. You get 2.06 Liters

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