chemistry
posted by lola .
a 2.00 L ballon at 25 degrees celcius and 745mmHg floats on an altitude where the temperature is 10 degrees celcius and the air pressure is 700mmHg. what is the new volume othe balloon

Use the combined gas law:
P1V1/T1=P2V2/T2
Where
P1=745mmHg
V1=2.00L
T1=273K+25=298.15K
P2=700mmHg
V2=?
T2=273.15+10=283.15K
Solve for V2:
V2=(P1/P2)*(T2/T1)*V1
Answer should contain three significant figures. 
1.06L

Convert pressures from mmHg to atm then use combined gas law to solve for the new volume. You get 2.06 Liters