The length of a rectangular piece of steel in a bridge is 3 meters less then double the width. The perimeter of the piece of steel is 24 meters Find the length and width of the piece of steel.

l=3-2w? is part of the formula?

Your definition of L is opposite of what it should be

L = 2W - 3

now use your definition of perimeter to solve

Perimeter of a rectange = 2W + 2L
2W + 2(2W-3) = 24
2W + 4W - 6 = 24
6W = 30
W = 5

then L = 2(5)-3 = 7

Your rectangle is 5 by 7
check:
P = 2(5)( + 2(7) = 10+14 = 24

Oh I got the formula backwards just had to flip it around. So yeah I got

L= 7 for the length of the piece of steel

and W=5 for the width of the piece of steel. I checked it and I got the same answer.

To find the length and width of the rectangular piece of steel, let's assign some variables:

Let's say that the width of the piece of steel is represented by "w" meters.

According to the problem, the length of the piece of steel is 3 meters less than double the width, which can be expressed as:

Length = 2w - 3 meters

To find the perimeter, we need to add up the lengths of all four sides of the rectangle, which is given as 24 meters.

Perimeter = 2(width) + 2(length)

So, we can write the equation as:

24 = 2w + 2(2w - 3)

Simplifying the equation, we have:

24 = 2w + 4w - 6

Combining like terms, we get:

24 = 6w - 6

Adding 6 to both sides, we have:

30 = 6w

Dividing both sides by 6, we get:

w = 5

Now that we have the value of the width, we can substitute it back into the expression for the length to find its value:

Length = 2w - 3
Length = 2(5) - 3
Length = 10 - 3
Length = 7

Therefore, the length of the rectangular piece of steel is 7 meters, and the width is 5 meters.