A bag contains 5 green marbles, 8 red marbles, 11 orange marbles, 7 brown marbles, and 12 blue marbles. you choose a marble, replace it, and choose again. what is P(red then blue.)

43 marbles in all, so

P(red,blue) = 8/43 * 12/43

Steve is right, 8/43 * 12/43 = 96/1849 so D is the answer

The answer is D.

yeah the answer is 96/1849

Steve is still right! We miss you Steve you were a math genius!

I am sorry to hear that Steve is no longer with us. However, I am glad that this question was answered correctly.

To find the probability of drawing a red marble and then a blue marble with replacement, we need to calculate the probability of each event separately and then multiply them together.

First, let's find the probability of drawing a red marble. There are a total of 5 + 8 + 11 + 7 + 12 = 43 marbles in the bag. Of these, 8 are red. Thus, the probability of drawing a red marble is 8/43.

Next, let's find the probability of drawing a blue marble. Since we replace the marble after each draw, the total number of marbles remains the same. Out of the 43 marbles, 12 are blue. Therefore, the probability of drawing a blue marble is also 12/43.

To find the probability of both events happening, we multiply the probabilities together: (8/43) * (12/43) = 96/1849.

So, the probability of drawing a red marble and then a blue marble with replacement is 96/1849.