Posted by **Sandra** on Monday, May 5, 2014 at 5:20pm.

Multiply: (K+3)/(4K-2)*(12K^2 + 2k – 4)

• 3(k+3)/(3k+2)

• 3(k+3)(2k-1)/2

• (x-5)(3x+2)

• (x-5)(12x+8)

How?

11

- ALGEBRA -
**Steve**, Monday, May 5, 2014 at 5:58pm
well, 12k^2+2k-4 = 2(3k+2)(2k-1)

so, we have

(k+3)/2(2k-1) * 2(3k+2)(2k-1)

now the 2(2k-1) cancels, leaving

(k+3)(3k+2)

No idea about the 11.

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