ALGEBRA
posted by Sandra .
Multiply: (K+3)/(4K2)*(12K^2 + 2k – 4)
• 3(k+3)/(3k+2)
• 3(k+3)(2k1)/2
• (x5)(3x+2)
• (x5)(12x+8)
How?
11

well, 12k^2+2k4 = 2(3k+2)(2k1)
so, we have
(k+3)/2(2k1) * 2(3k+2)(2k1)
now the 2(2k1) cancels, leaving
(k+3)(3k+2)
No idea about the 11.