Tuesday
September 2, 2014

Homework Help: Chem

Posted by Anonymous on Monday, May 5, 2014 at 2:47pm.

The following results were obtained when a sample of pineapple juice was analyzed to determine its vitamin C content. A 19.8 mL sample of pineapple juice was placed in a flask with 20 ml of 0.5 M H2SO4, 1.0 g of potassium iodide, KI, and 25.00 mL of 0.01988 M potassium iodate, KIO3. Titration with sodium thiosulfate required the use of 23.85 mL of 0.08014 M Na2S2O3. Calculate the concentration of vitamin C in the sample in mg vitamin C per 100 mL juice.

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