Balance the following equation for a half reaction that occurs in basic solution. Use e– as the symbol for an electron.
SO3^2- ---> S2O4^2-
Chemistry - DrBob222, Sunday, May 4, 2014 at 11:47pm
I shall be glad to help you through this but you need to learn to do these yourself. I do these the looong way. The first step is to determine the oxidation step of each element. I will help you here. S on the left is +4 and on the right is +6. Add electrons to the appropriate side to balance the change in oxidation number.
SO3^2- ==> SO4^2- + ?e
Chemistry - BOB, Monday, May 5, 2014 at 12:10am
H2O + SO3^2- ---> SO4^2- +2H^+ + 3e^-
Chemistry - BOB, Monday, May 5, 2014 at 12:14am
Nevermind I figured it out its:
2SO3^2- + 2H2O + 2e^- ---> S2O4^2- + 4OH^-
Chemistry - DrBob222, Monday, May 5, 2014 at 12:21am
You changed SO4^2- on the right to S2O4^2- and you can't do that. Also you have the e on the wrong side. Other than that it is ok.
2OH^- + SO3^2- ==> SO4^2- + 2e + H2O
Chemistry - dr, Monday, July 21, 2014 at 10:18am
DrBob222 you're wrong.
Chemistry - Jay, Monday, November 16, 2015 at 11:12am
2 SO3^-2 + 2 H2O + 2e- -> S2O4^-2 + 4OH-