Can CoBr2+ NH4Br + NH4OH ---> Co^2+ (aq) + 2NH3 (l) + H^+ (aq) + H2O (l) + 3Br^- form the complex [Co(NH3)5Br]Br2 if so please explain
Yes, the reaction you mentioned can indeed form the complex [Co(NH3)5Br]Br2.
To understand how this complex is formed, let's break down the reaction step by step:
1. CoBr2 dissociates into Co^2+ ions and Br^- ions. This is represented by the equation:
CoBr2 → Co^2+(aq) + 2Br^-(aq)
2. NH4Br also dissociates into NH4+ ions and Br^- ions. This is represented by the equation:
NH4Br → NH4+(aq) + Br^-(aq)
3. NH4OH dissociates into NH4+ ions and OH^- ions, but it also reacts with H^+ ions to form water (H2O). This reaction can be represented as:
NH4OH + H^+ → NH4^+(aq) + H2O(l)
4. The Co^2+ ions from step 1, the NH4+ ions from step 2, and the Br^- ions from steps 1 and 2 can combine to form a complex. The Co^2+ ion can bond with five NH3 molecules and one Br^- ion. This complex is represented by the formula [Co(NH3)5Br]^2+. Therefore, the reaction is:
Co^2+(aq) + 5NH3(aq) + Br^-(aq) → [Co(NH3)5Br]^2+(aq)
5. Finally, the excess H^+ ions from step 3 combine with OH^- ions to form water (H2O). This reaction is represented by the equation:
H^+(aq) + OH^-(aq) → H2O(l)
So, the overall balanced equation for the reaction you mentioned is:
CoBr2 + NH4Br + NH4OH → [Co(NH3)5Br]Br2 + H2O + H^+ + 3Br^-
In this reaction, CoBr2, NH4Br, and NH4OH react to form the complex [Co(NH3)5Br]Br2, along with water, H^+ ions, and Br^- ions.