Let say that Amy made 8 out of 21 free throws and Jane made 4 out of 21 free throws. Who had the better rate of success? Round your answer to the nearest percent.
Divide and multiply by 100.
8/21 = 38%
4/21 = 19%
To determine who had the better rate of success, we need to calculate the success rate for both Amy and Jane.
Amy made 8 out of 21 free throws. To calculate her success rate, divide the number of successful attempts by the total number of attempts and multiply by 100:
Success rate for Amy = (8/21) * 100
Jane made 4 out of 21 free throws. To calculate her success rate, divide the number of successful attempts by the total number of attempts and multiply by 100:
Success rate for Jane = (4/21) * 100
Let's calculate these success rates:
Success rate for Amy = (8/21) * 100 = 38.09524
Success rate for Jane = (4/21) * 100 = 19.04761
Rounding to the nearest percent, we find that Amy has a success rate of 38% and Jane has a success rate of 19%. Therefore, Amy had the better rate of success.
To determine who had the better rate of success, we need to compare the success rates of Amy and Jane.
To find the success rate, we divide the number of successful free throws by the total number of attempts and multiply by 100 to get a percentage.
For Amy:
Number of successful free throws = 8
Total number of attempts = 21
Amy's success rate = (8/21) * 100 ≈ 38.1% (rounded to the nearest percent)
For Jane:
Number of successful free throws = 4
Total number of attempts = 21
Jane's success rate = (4/21) * 100 ≈ 19.0% (rounded to the nearest percent)
Comparing the success rates, we see that Amy had a higher rate of success with approximately 38.1%, while Jane had a success rate of approximately 19.0%. Therefore, Amy had the better rate of success.