A vibrating point on a spring travels 60 mm during three cycles. What is the amplitude of the vibration?
first half cycle it goes up then down, second half cycle it goes up then down.
now do this three times...
first cycle: 4A
second cycle: 4A
three cycles= 12 A
a= 5mm
Why did the point go on a spring break? Because it wanted to have a bouncing good time! Now, to answer your question, if the vibrating point travels 60 mm during three cycles, we can divide the distance traveled by the number of cycles to find the amplitude. So, 60 mm divided by 3 cycles gives us an amplitude of 20 mm. Just enough spring in its step!
To find the amplitude of vibration, we need to determine the maximum displacement of the vibrating point on the spring. The amplitude represents the distance from the equilibrium position to the maximum displacement.
Given that the vibrating point on the spring travels 60 mm during three cycles, we can divide the total displacement by the number of cycles to find the displacement per cycle.
Total displacement = 60 mm
Number of cycles = 3
Displacement per cycle = Total displacement / Number of cycles
Displacement per cycle = 60 mm / 3 = 20 mm
Since the displacement per cycle represents the distance from the equilibrium position to the maximum displacement, the amplitude of the vibration is 20 mm.
To find the amplitude of the vibration, we need to divide the total distance traveled by the number of cycles.
In this case, the total distance traveled is 60 mm and the number of cycles is 3.
So, we can calculate the amplitude using the formula:
Amplitude = Total Distance Traveled / Number of Cycles
Amplitude = 60 mm / 3 = 20 mm
Therefore, the amplitude of the vibration is 20 mm.