Sunday
March 26, 2017

Post a New Question

Posted by on .

A 4.07 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring constant is 144 N/m. The block is shoved parallel to the spring axis and is given an initial speed of 10.5 m/s, while the spring is initially unstrained. What is the amplitude of the resulting simple harmonic motion?

  • Physics - ,

    well, the initial KE= 1/2 m v^2 which is given. At full extension, the PE stored is 1/2 k x^2

    x is the amplitude, solve for it.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question