Calculus/Physics
posted by Tim on .
It took 1800J of work to stretch a spring from its natural length of 2m to a length of 5m. Find the spring's force constant.

W = F*d = F * (52) = 1800 Joules.
3F = 1800
F = 600 N.
k = 600N./3m = 200N/m
posted by Tim on .
It took 1800J of work to stretch a spring from its natural length of 2m to a length of 5m. Find the spring's force constant.
W = F*d = F * (52) = 1800 Joules.
3F = 1800
F = 600 N.
k = 600N./3m = 200N/m