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posted by Tim Friday, May 2, 2014 at 9:38am.
It took 1800J of work to stretch a spring from its natural length of 2m to a length of 5m. Find the spring's force constant.
W = F*d = F * (5-2) = 1800 Joules. 3F = 1800 F = 600 N. k = 600N./3m = 200N/m
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