a glider flies 8 miles south then 15 miles east then flies in a straight line back to the airport. what was the distance of the gliders last leg back to the air port
Use the Pythagorean Theorem as I showed you in your last postr.
so 8^2 + 15^ = k^2
64 + 225 = k^2
289 = k^2
17 = k
Right!
To find the distance of the glider's last leg back to the airport, we need to use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the glider flew 8 miles south (which would be the vertical leg of the triangle) and 15 miles east (which would be the horizontal leg of the triangle). So, we have a right triangle with sides of lengths 8 and 15.
Using the Pythagorean theorem:
Hypotenuse^2 = 8^2 + 15^2
Hypotenuse^2 = 64 + 225
Hypotenuse^2 = 289
Taking the square root of both sides, we find:
Hypotenuse ≈ √289
Hypotenuse ≈ 17
Therefore, the distance of the glider's last leg back to the airport is approximately 17 miles.