Child 1 is 2.0 m from the axis of rotation, and child 2 is 1.5 m from the axis. The merry-go-round completes one revolution every 4.8 s.
Find the angular speed of each child. (Answer: For both child is 0.278rev/s)
Please show all work on how to get the answer.
To find the angular speed of each child, we can use the formula:
Angular speed (ω) = 2π / time period (T)
First, let's calculate the time period of one revolution:
T = 4.8 s
Next, we can calculate the angular speed for each child using their respective distances from the axis of rotation.
For Child 1:
Radius (r₁) = 2.0 m
Angular speed of Child 1 (ω₁) = 2π / T
= 2π / 4.8 s
Now, let's calculate it:
ω₁ = 2π / 4.8
≈ 0.2618 rad/s
For Child 2:
Radius (r₂) = 1.5 m
Angular speed of Child 2 (ω₂) = 2π / T
= 2π / 4.8 s
Now, let's calculate it:
ω₂ = 2π / 4.8
≈ 0.2618 rad/s
So, the angular speed of both Child 1 and Child 2 is approximately 0.278 rad/s.