Please help me write these two balanced equations.
Dissolution of rust, Fe2O3, by sulfuric acid.
and
Ammonium nitrite reacts with oxygen to form ammonium nitrate.
Any help would be awesome, thankyou.
I think I got the answer for the second one
ammonium nitrite reacts with oxygen to form ammonium nitrate:
2NH4NO2+O2=2NH4NO5
OK except NH4NO5 is not ammonium nitrate. That's NH4NO3.
2NH4NO2 + O2 ==> 2NH4NO3
Fe2O3 + 3H2SO4 ==> Fe2(SO4)3 + 3H2O
Sure! I'd be happy to help you write these balanced equations. Let's start with the first one:
Dissolution of rust, Fe2O3, by sulfuric acid.
To balance this equation, we need to make sure that the number of atoms on both sides of the equation is equal. Here's the balanced equation:
Fe2O3 + 3H2SO4 -> Fe2(SO4)3 + 3H2O
In this balanced equation, there are equal numbers of iron (Fe), oxygen (O), sulfur (S), and hydrogen (H) atoms on both sides.
Now, let's move on to the second equation:
Ammonium nitrite reacts with oxygen to form ammonium nitrate.
To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal. Here's the balanced equation:
NH4NO2 + O2 -> NH4NO3
In this balanced equation, there are equal numbers of nitrogen (N), hydrogen (H), and oxygen (O) atoms on both sides.
Remember, when balancing equations, start by balancing the atoms that appear in the fewest compounds first, and then balance the atoms in more complex compounds.
I hope this helps! Let me know if you have any further questions.