a carnot heat engine operates between reservoirs at 550K and 300K, discarding 1500J of heat in each cycle.

A) What is the engine's efficiency?
B) How much heat is supplied to the engine by the hot reservoir in each cycle?

To calculate the efficiency of a Carnot heat engine, you need to use the formula:

Efficiency = (1 - Tc/Th) * 100%

Where Tc is the temperature of the cold reservoir and Th is the temperature of the hot reservoir, both in Kelvin.

A) To find the engine's efficiency, you can plug in the given values:

Efficiency = (1 - Tc/Th) * 100%
= (1 - 300K/550K) * 100%
≈ 45.45%

Therefore, the efficiency of the Carnot heat engine is approximately 45.45%.

B) The amount of heat supplied to the engine by the hot reservoir in each cycle can be calculated using the equation:

Qh = Efficiency * Qc

Where Qh is the heat supplied by the hot reservoir, Efficiency is the engine's efficiency, and Qc is the heat discarded in each cycle.

Substituting the given values:

Qh = Efficiency * Qc
= (45.45% * 1500J)
≈ 683.25J

Therefore, the amount of heat supplied to the engine by the hot reservoir in each cycle is approximately 683.25J.

niger