If 9 apples plus 4 pears cost $2.6 and if 4 pears pluse 9 apples cost $1.90 what does each apple and pear cost

Assuming the obvious typo, we have

9a+4p = 260
4a+9p = 190

which does not have an integer solution. So, maybe there's something else you need to fix.

Do you see your mistake in this problem?

To find out the cost of each apple and pear, we can set up a system of equations based on the given information.

Let's assume the cost of each apple is A dollars, and the cost of each pear is P dollars.

From the first statement "9 apples plus 4 pears cost $2.6," we can write the equation:

9A + 4P = 2.6 (Equation 1)

From the second statement "4 pears plus 9 apples cost $1.90," we can write the equation:

4P + 9A = 1.9 (Equation 2)

To solve this system of equations, we can use a method called substitution:

Step 1: Solve Equation 1 for A:
9A = 2.6 - 4P
A = (2.6 - 4P) / 9

Step 2: Substitute the value of A in Equation 2:
4P + 9((2.6 - 4P) / 9) = 1.9

Simplifying this equation:
4P + 2.6 - 4P = 1.9
2.6 = 1.9

This equation does not have any solution. The given information seems to have inconsistencies, as it leads to a contradiction. It's not possible for both statements to be true simultaneously.

Therefore, we cannot determine the individual cost of each apple and pear based on the provided information.