A steel reinforcing rod is 12 ft. long and 1" thick in diameter. If a cubic foot of steel weighs 490 lb., how much does the rod weigh (to the nearest pound)?

To find the weight of the steel rod, we need to first calculate its volume and then multiply it by the weight per cubic foot.

The formula for calculating the volume of a cylinder is:

Volume = π * radius^2 * height

Given that the diameter of the reinforcing rod is 1", the radius would be half of that:

Radius = 1" / 2 = 0.5"

Converting the radius to feet:

Radius = 0.5" / 12 = 0.0417 ft

The height of the rod is given as 12 ft.

Now we can calculate the volume:

Volume = π * (0.0417 ft)^2 * 12 ft
≈ 0.00908 ft^3

Finally, we can calculate the weight of the rod:

Weight = Volume * Weight per cubic foot
= 0.00908 ft^3 * 490 lb/ft^3
≈ 4.4572 lb

Therefore, the rod weighs approximately 4.4572 pounds when rounded to the nearest pound.

To find the weight of the steel reinforcing rod, we need to calculate its volume first. Here's how you can do that:

1. Find the radius of the rod: The diameter of the rod is given as 1 inch, so the radius (r) is half of the diameter, which is 1/2 inch or 0.5 inches.

2. Convert the radius to feet: Since the length of the rod is given in feet, we need to convert the radius to feet as well. There are 12 inches in a foot, so the radius in feet would be 0.5 inches / 12 = 0.0417 feet.

3. Calculate the volume of the rod: The volume of a cylinder (which is the shape of the rod) can be calculated using the formula V = πr^2h, where V is the volume, r is the radius, and h is the height or length. Substitute the values into the formula:

V = π * (0.0417 ft)^2 * 12 ft

V ≈ 0.081 cubic feet (rounded to three decimal places)

4. Find the weight of the rod: Now that we know the volume, we can calculate the weight. The weight of the steel is given as 490 lb per cubic foot. Multiply the volume by the weight per cubic foot:

Weight = 0.081 cubic feet * 490 lb/cubic foot

Weight ≈ 39.69 lb (rounded to the nearest pound)

Therefore, the steel reinforcing rod weighs approximately 39.69 pounds.

lee wants to cut this piece of canvas into two rectangles that are 3 times 2 and 3 times 5 he wants the sum of the areas of the two small rectangles to be the same as the area of the large rectangle can he do this explain

V = pi*r^2 * L = pi * (0.5/12)^2 * 12 =

5.45*10^-3 Ft^3. = Vol. of rod.

Wt.=490Lbs/Ft^3 * 5.45*10^-3Ft^3 = 2.67
Lbs.