Physics
posted by Joe on .
An artificial satellite circles the Earth in a circular orbit at a location where the acceleration due to gravity is 8.26 m/s2. Determine the orbital period of the satellite.

v^2/r = 8.26
F/m = local g = G M/r^2 = 8.26
6.67*10^11 * Mass earth/r^2 = 8.26
solve that for r
then
v^2 = 8.26 r
solve for v
v T = 2 pi r
T = 2 pi r/v