Karen sells tickets a movie theater. Last night she sold 128 tickets for a total of $1108. Adult's tickets cost $10 and children's tickets cost $6 how many of eac h kind of ticket did karen sell?

oops its 85 adult tickets and 43 children tickets my bad

10A+6C=1108

A+C=128

no idea

45

To determine the number of adult and children's tickets sold by Karen, we can set up a system of equations based on the given information.

Let's assume Karen sold x adult tickets and y children's tickets.

The total number of tickets sold is 128, so we can write the first equation as:
x + y = 128

The total revenue from ticket sales is $1108, so we can write the second equation as:
10x + 6y = 1108

Now, we can solve this system of equations to find the values of x and y.

First, let's solve the first equation for x:
x = 128 - y

Next, substitute this expression for x into the second equation:
10(128 - y) + 6y = 1108

Now, simplify and solve for y:
1280 - 10y + 6y = 1108
-4y = 1108 - 1280
-4y = -172
y = -172 / -4
y = 43

So, Karen sold 43 children's tickets.

Substitute the value of y back into the first equation to find x:
x + 43 = 128
x = 128 - 43
x = 85

Therefore, Karen sold 85 adult tickets.

In conclusion, Karen sold 85 adult tickets and 43 children's tickets.