A cue ball collides with two other snooker balls and comes to a complete stop. The

angles between the centres at the point of collision are shown below. If the velocity
of the incoming cue ball is 5 m/s, determine the velocities of all moving balls after
the collision.

To determine the velocities of the balls after the collision, we can make use of the principles of conservation of momentum and conservation of kinetic energy.

Let's assign some variables to the velocities of the balls:
- v1 for the velocity of the cue ball after the collision
- v2 for the velocity of the first snooker ball after the collision
- v3 for the velocity of the second snooker ball after the collision

According to the principle of conservation of momentum, the total momentum before the collision should be equal to the total momentum after the collision. The momentum of an object is given by the product of its mass and velocity.

We can express this mathematically as:
m1 * v1(initial) + m2 * v2(initial) + m3 * v3(initial) = m1 * v1(final) + m2 * v2(final) + m3 * v3(final)

Here, m1, m2, and m3 represent the masses of the cue ball, the first snooker ball, and the second snooker ball, respectively.

Since we know the velocity of the incoming cue ball (v1(initial) = 5 m/s) and the angles between the centers of the balls, we can use the law of cosines to find the initial velocities of the snooker balls before the collision.

Let's assume that the masses of all three balls are equal (m1 = m2 = m3 = m)

The law of cosines states that:
c^2 = a^2 + b^2 - 2ab * cos(C)

In this case, the initial velocities v2(initial) and v3(initial) are represented by b and c, respectively. The angle between the centers is represented by C.

Using the given angle measurements and the law of cosines, we can calculate the initial velocities of balls 2 and 3.

After determining the initial velocities, we can use the principle of conservation of kinetic energy to find the final velocities of the balls after the collision.

The equation for kinetic energy is given by:
KE = 0.5 * mass * velocity^2

To solve for the final velocities, we can set up an equation to equate the total kinetic energy before the collision to the total kinetic energy after the collision.

0.5 * m * (v1(initial)^2 + v2(initial)^2 + v3(initial)^2) = 0.5 * m * (v1(final)^2 + v2(final)^2 + v3(final)^2)

Simplifying and solving this equation will allow us to determine the final velocities v1(final), v2(final), and v3(final).

Note: It's important to use consistent units for all measurements (e.g., meters for lengths and seconds for time) and ensure that the angles provided are measured accurately.

To solve this problem, we can use the principles of conservation of momentum and conservation of kinetic energy. Let's denote the velocities of the cue ball, first snooker ball, and second snooker ball as v1, v2, and v3 respectively.

1. Conservation of Momentum:
According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Initial momentum = Final momentum

Since the cue ball comes to a complete stop after the collision, the initial momentum is given by:
Initial momentum = mass of cue ball * velocity of cue ball = m1 * v1

After the collision, the final momentum is given by:
Final momentum = mass of cue ball * 0 + mass of first snooker ball * v2 + mass of second snooker ball * v3

Since the masses of all the balls are equal in snooker, let's assume the mass (m) for simplicity. Therefore, we have:
m1 * v1 = m * v2 + m * v3

2. Conservation of Kinetic Energy:
According to this principle, the total kinetic energy before the collision is equal to the total kinetic energy after the collision.

Initial kinetic energy = Final kinetic energy

As the cue ball comes to a complete stop, the initial kinetic energy is given by:
Initial kinetic energy = 0.5 * mass of cue ball * (velocity of cue ball)^2 = 0.5 * m1 * (v1)^2

After the collision, the final kinetic energy is given by:
Final kinetic energy = 0.5 * mass of cue ball * (0)^2 + 0.5 * mass of first snooker ball * (v2)^2 + 0.5 * mass of second snooker ball * (v3)^2

Simplifying, we have:
0.5 * m1 * (v1)^2 = 0.5 * m * (v2)^2 + 0.5 * m * (v3)^2

Now, we have two equations with two unknowns (v2 and v3). We can solve these equations simultaneously to find the values of v2 and v3.

Let's proceed with the calculations.