I need help to evaluate if I completed my experiment calculation.
determination of water in a hydrate.
1. Mass of crucible, and cover = 18451.3
2. Mass of crucible, cover and sample = 23410.2
3. Mass of crucible, cover and sample after 1st heating = 21789.8
4. Mass of crucible, cover and sample after 2nd heating = 2116.6
I need to find the:
5. Mass of original sample & show calculation setup.
6. Total mass lost by sample during heating & show calculation setup.
7. Percentage water in sample & show water in sample & show calculation.
For # 5 I subtracted 18451.3 from 23410.2 and got 4958.9
For # 6 I subtracted 2116.6 from 4958.9 and got 2842.3.
I think the formula for #8 is % of h20 = 4958.9/2842.3 times 100, and I got 57.317 which would be 57.2.
For some reason I think that I am suppose to use some sort of formulas for question # 5 & 6. Please help me thank you.
I can't believe the numbers are right for all entries. For example, when I look at 23410.2-21789.6 for mass after first heating ( a loss of 1620.7) then loss after second heating of 2116.6 that's
21789.8-2116.6 = that's 19,673.2 which is unbelievable between heatings. Are you sure all of the digits are in that 2116.6 number?
To evaluate if you completed your experiment calculation, let's go through each question and check your answers:
1. Mass of crucible and cover = 18451.3
2. Mass of crucible, cover, and sample = 23410.2
3. Mass of crucible, cover, and sample after 1st heating = 21789.8
4. Mass of crucible, cover, and sample after 2nd heating = 2116.6
Now let's calculate your answers:
5. Mass of original sample:
To find the mass of the original sample, you are correct. You subtract the mass of the crucible and cover (18451.3) from the mass of the crucible, cover, and sample (23410.2):
Original sample mass = 23410.2 - 18451.3 = 4958.9
Your calculation is correct.
6. Total mass lost by the sample during heating:
To find the total mass lost by the sample during heating, you subtract the mass of the crucible, cover, and sample after the 2nd heating (2116.6) from the mass of the original sample (4958.9):
Total mass lost = 4958.9 - 2116.6 = 2842.3
Your calculation is correct.
7. Percentage water in the sample:
To find the percentage of water in the sample, you need to use the formula: (mass of water / mass of original sample) * 100.
Since the mass of water is not given explicitly, you can calculate it using the mass lost by the sample during heating.
Mass of water lost = Total mass lost (2842.3)
Percentage water in the sample = (mass of water lost / mass of original sample) * 100 = (2842.3 / 4958.9) * 100 ≈ 57.39%
Your calculation is close, but rounded incorrectly. The correct answer is approximately 57.39%.
Overall, your calculations are correct, but for question #7, you made a slight error in rounding. Make sure to check your rounding and ensure you are using the correct formulas for each calculation.