F(x)=x^2-2x-3
plz help me slove this ?
HELP ME I DO NOT UNDERSTAND THIS HELP ME PLZ
Well, you really did not ask a question. All you did was give the equation fort a parabola. So what?
y = x^2 - 2 x - 3
do you want to know where that is zero? Where the vertex is? how it looks?
if you want the two zeros, just factor it
y = (x-3)(x+1)
that is zero when:
x = 3
and when
x = -1
so the vertex is halfway between
x = (3-1)/2 = 1
then y = 1-2-3 = -4
so vertex at (1,-4)
what else about it?
OH OK I TELL YOU
To solve the equation f(x) = x^2 - 2x - 3, we need to find the values of x that make the equation true.
Step 1: Set f(x) equal to zero: x^2 - 2x - 3 = 0
Step 2: Factorize or use the quadratic formula to solve for x.
In this case, the equation can be factored as (x - 3)(x + 1) = 0
Step 3: Set each factor equal to zero and solve for x:
x - 3 = 0 --> x = 3
x + 1 = 0 --> x = -1
So, the solutions to the equation f(x) = x^2 - 2x - 3 are x = 3 and x = -1.