Post a New Question

Physics 194

posted by on .

Light of wavelength 630 nm passes through a grating and then onto a screen located several meters from the grating. The 1st order bright band is located 0.26m from the central maximum. Light from a second source produces a band 0.21m from the central maximum.

Determine the wavelength of the second source. [Hint: If the angular deflection is small, tan θ = sin θ.]

  • Physics 194 - ,

    d•sinφ=kλ,
    tanφ=x/L. =>
    d•x/L=kλ
    λ₁=dx₁/Lk
    λ₂=dx₂/Lk
    λ₁/λ₂=dx₁Lk/dx₂Lk= x₁/x₂
    λ₂=λ₁x₂/x₁=630•0.21/0.26=508 nm

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question