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August 2, 2014

Homework Help: Chemistry

Posted by Alexis on Friday, April 25, 2014 at 3:51am.

At 25 C, the equilibrium partial pressures for the following reaction were found to be PA = 4.10 bar, PB = 5.60 bar, PC = 1.20 bar, and PD = 9.70 bar.

2A(g)+2B(g)-->C(g)+ 3D(g)

What is the standard change in Gibbs free energy of this reaction at 25 C.

I don't really get how to even start the problem because I never seen partial pressure in the Gibb free energy. I just know that delta G = -RTlnK.

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